Technical /logical interview questions and solution in C language

1.)

void main()

  {

   int  const * p=5;

   printf("%d",++(*p));

  }

Answer:

Compiler error: Cannot modify a constant value. 

Explanation:-    

p is a pointer to a "constant integer". But we tried to change the value of the "constant integer".

2.)

main()

   {

    char s[ ]="man";

    int i;

    for(i=0;s[ i ];i++)

    printf("\n%c%c%c%c",s[ i ],*(s+i),*(i+s),i[s]);

   }

Answer:

             mmmm

                aaaa

                nnnn

Explanation:-

s[i], *(i+s), *(s+i), i[s] are all different ways of expressing the same idea. Generally  array name is the base address for that array. Here s is the base address. i is the index number/displacement from the base address. So, indirecting it with * is same as s[i]. i[s] may be surprising. But in the  case of  C  it is same as s[i].

3.)

main()

  {

   float me = 1.1;

   double you = 1.1;

   if(me==you)

   printf("I love U");

   else

   printf("I hate U");

  }

Answer: 

I hate U

Explanation:-

For floating point numbers (float, double, long double) the values cannot be predicted exactly. Depending on the number of bytes, the precession with of the value  represented varies. Float takes 4 bytes and long double takes 10 bytes. So float stores 0.9 with less precision than long double.

Rule of Thumb: 

Never compare or at-least be cautious when using floating point numbers with relational operators (== , >, <, <=, >=,!= ) .  

4.)

main()

   {

   static int var = 5;

   printf("%d ",var--);

   if(var)

   main();

   }

Answer:

5 4 3 2 1

        

Explanation:

When static storage class is given, it is initialized once. The change in the value of a static variable is retained even between the function calls. Main is also treated like any other ordinary function, which can be called recursively.  

5.)

main()

  {

   int c[ ]={2.8,3.4,4,6.7,5};

   int j,*p=c,*q=c;

   for(j=0;j<5;j++)>

   printf(" %d ",*c);

   ++q;  

  }

  for(j=0;j<5;j++)

  {

   printf(" %d ",*p);

   ++p;  

 }

}

Answer:

             2 2 2 2 2 2 3 4 6 5

  

Explanation: 

Initially pointer c is assigned to both p and q. In the first loop, since only q is incremented and not c , the value 2 will be printed 5 times. In second loop p itself is incremented. So the values 2 3 4 6 5 will be printed. 

ALL PLACEMENT TECHNICAL INTERVIEW C PROGRAMMING LANGUAGE QUESTION  BANCK   

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